Division Method Of Square Root Class 8
Division Method Of Square Root Class 8
Exercise
Q1. Find the square root of each of the following numbers by division method :
i) 576
2 | 5 76 | 24
2 | 4
44 | 1 76
4 | 1 76
48 | 0
√576 = 24
ii) 961
3 | 9 61 | 31
3 | 9
61 | 0 61
1 | 61
62 | 0
√961 = 31
iii)1444
3 | 14 44 | 38
3 | 9
68 | 5 44
8 | 5 44
76 | 0
√1444 = 38
iv) 4489
6 | 44 89 | 67
6 | 36
127 | 8 89
7 | 8 89
134 | 0
√4489 = 67
v) 6241
7 | 62 41 | 79
7 | 49
149 | 13 41
9 | 13 41
158 | 0
√6241 = 79
vi) 5476
7 | 54 76 | 74
7 | 49
144 | 5 76
4 | 5 76
148 | 0
√5476 = 74
vii) 9025
9 | 90 25 | 95
9 | 81
185 | 9 25
5 | 9 25
170 | 0
√9025 = 95
viii) 7569
8 | 75 69 | 87
8 | 64
167 | 11 69
7 | 11 69
174 | 0
√7569 = 87
Q2. The area of a square field is 7744 sq. metres. Find its perimeter.
Area of square = side *side
side = √7744
8 | 77 44 | 88
8 | 64
16 8 | 13 44
8 | 13 44
17 6 | 0
√7744 = 88
Side = 88 m
Perimeter = 4 * side
= 4 * 88
= 352 m
Q3. Find the least number which must be subtracted from 1104 to obtain a perfect square find this perfect square and eight square root
Let us try to find the square root of 1104.
3 | 11 04 | 33
3 | 9
6 3 | 2 04
3 | 1 89
6 6 | 15
Clearly 332 is less than 1104 by 15.
So, the least number to be subtracted from 1104 to get a perfect square = 15
Resulting perfect square number = 1104 - 15 = 1089
√1089 = 33
Q4. Find the least number which must be added to 6203 to obtain a perfect square. Find the perfect square and its square root.
Let us try to find the square root of 6203.
7 | 62 03 | 78
7 | 49
148 | 13 03
8 | 11 84
156 | 1 19
Clearly, 782 < 6208 < 792
Required number to be added = 792 - 6208 = 6241 - 6203 = 38
Resulting number = 6203 + 38 = 6241 = 792
Square root of resulting number = 79
Q 5. Find the greatest number of 6 digits which is a perfect square. Find the square root of this number.
Greatest number of 6 digits = 999999
Let us try to find the square root of 9999999.
9 | 99 99 99 | 999
9 | 81
189 | 18 99
9 | 17 01
1989 | 1 98 99
| 1 79 01
| 0 19 98
Clearly, 9992 is the less than 999999 by 1998.
So, the least number to be subtracted is 1998.
Hence required number = 99999 - 1998 = 998001.
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