IMO Previous Year Paper Solution class 7
SOF International Mathematics Olympiad 2020 Paper class 7
Logical Reasoning
1. In the given figure, the triangle represents leaders, rectangle represents honest people and circle represents biased people. Which of the following represents honest leaders who are not biased?
A. 4
B. 5
C. 6
D. 7
Ans : 1. (B): 5 is common in rectangle and triangle only. So, 5 represents honest leaders who are not biased.
2. If each vowel is removed from the given below arrangement, then which of the following is 6th to the left of 8th element from the right end?
M P x q - e L i J #d e F @ z t M 8 A 1 p r t * 7 q d
A. @
B. d
C. F
D. #
Ans : 2. (C): After removing all the vowels, the new arrangement becomes
M P x q - L J #d F @ z t M 8 1 p r t * 7 q d
8th element from right end is 1 and 6th to the left of 1 is F.
3. If in a certain code language, FEMALE is coded as HODPHI, then how will FACING be coded in that language?
A. IPDLHQ B. JPLFEJ
C. JQLEEI D. JQLFDI
Ans : 3. (D): We have,
FEMALE reverse ELAMEF
Now, E L A M E F
+3 +3 +3 +3 +3 +3
H O D P H I
Similarly, FACING reverse GNICAF
Now, G N I C A F
+3 +3 +3 +3 +3 +3
J Q L F D I
4. A sheet of paper is folded in a particular manner and a punch is made as shown. Select a figure from the options that would most closely resembles the unfolded form of the given sheet.
Ans : 4. (B)
5. Find the minimum number of straight lines required to form the given figure.
C. 15 D. 18
Ans ; 5. (A): Straight lines required are: AB, BC, CD, DE, EG, GH, HA, DJ, JK, KC, AN, LM, MF, NF, HP, NP i.e. 16 in number.
6. Select the correct water image of the given figure.
7. Which of the following will be the second highest number, if middle digit and last digit of each of the given numbers are decreased and increased by 1 respectively?
846, 942, 695, 786, 895
A. 942
B. 846
C. 895
D. 786
Ans : 7. (C): After decreasing and increasing the middle digit and last digit by 1,
we get 837, 933, 686, 777, 886
So, second highest number is 886, which comes from 895.
8. Which of the following options will complete the pattern in the given figure?
9. Which of the following elements satisfies the given Venn diagram?
A. Fathers, Males, Girls
B. Teachers, School, Students
C. Indians, Surgeons, Doctors
D. Pigeons, Birds, Sparrows
10. Which of the following options does not satisfy the same conditions of placement of dots as in the given figure?
11. If it is possible to make a meaningful English word using the first, fourth, sixth, eighth and tenth letter of the word AGGRESSIVE, then the second letter of that word is the answer. If no such meaningful word is formed, then give ‘X’ as answer. If more than one such word is formed, then give ‘M’ as answer.
A. M
B. A
C. E
D. X
Ans .11. (A): The first, fourth, sixth, eighth and tenth letters of the word AGGRESSIVE are: A, R, S, I and E. So, words formed are: ARISE, RAISE, etc.
12. There is a certain relationship between figures (i) and (ii). Establish the same relationship between figures (iii) and (iv) by selecting a suitable figure from the options that will replace (?) in fig. (iv). ?
Ans:12. (A)
13. Select a figure from the options which will complete the given figure matrix.?
Ans :13. (A): In each row, third figure is obtained by joining first two figures.
14. M, N, O, P, Q, R, S and T are sitting in a row facing North.
(i) S is at 3rd position from the left end.
(ii) P is the neighbour of Q and M. M is at one of the ends.
(iii) The person who is 4th to the left of N is at the other end.
(iv) T is not a neighbour of N who is to the immediate right of O. If R is at the first position, then who two are in the middle?
A. N, S
B. P, Q
C. O, N
D. O, Q
Ans .14. (C): The sitting arrangement is as follows: R T S O N Q P M
O and N are in the middle.
15. How many pairs of letters are there in the word CONSONANT each of which have same number of letters between them as in the English alphabets?
A. Two
B. One
C. Three
D. More than three
Ans. 15. (C):
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Mathematical Reasoning
16. How many more squares must be shaded so that the given figure has 2/5 as unshaded fraction?
A. 8 B. 6
C. 5 D. 7
Ans 16. (B): Total number of squares = 30
Number of unshaded squares needed = 2 / 5 × 30 = 12
Number of already unshaded squares = 18
So, 18 – 12 = 6 squares must be shaded.
17. Which of the following number line represents 0 –2 – 4?
Ans 17. (C)
18. Which rational number has to be multiplied with 64 to get the result − 49 3 / 5 ?
A. −35 / 43 B. −31 / 40
C. −33 / 40 D. −37 / 43
Ans 18. (B): Let the required rational number be X.
So, x * 64 = -49 3/5
= x = -248/5 * 1/64 = -31/40
Direction (19-20): The given double bar graph shows the various activities taken up by the boys and girls in a particular group. Study the graph carefully and answer the following questions.
19. What is the difference between the average number of boys and average number of girls taken all the activities together?
A. 10 B. 5
C. 3 D. 16
Ans 19. (C): Average number of boys = 15 + 20 +15 + 35 + 30 / 5 = 115 / 5 = 23
Average number of girls = 15 + 25 + 30 + 20 + 40 / 5 = 130 / 5 = 26
So, required difference = 26 – 23 = 3
20. Find the ratio of the number of boys taken Music and Art together to the number of girls taken Yoga and Karate together.
A. 7: 9 B. 7: 11
C. 9: 7 D. 8: 15
Ans 20. (C): Number of boys taken Music and Art together = 15 + 30 = 45
Number of girls taken Yoga and Karate together = 15 + 20 = 35
So, required ratio = 45 / 35 = 9 / 7 i.e. 9: 7
A. 1 / 4 B. 1 / 16
C. 1 / 64 D. 1 / 72
Ans 21. (C):
22. Prism is a polyhedron whose base and top are ____.
A. Congruent B. Similar
C. Proportional D. Different
Ans 22. (A)
23. In the figure (not drawn to scale), ABC is an equilateral triangle and ABD is an isosceles triangle with DA = DB, find the value of x.
A. 14° B. 16°
C. 12° D. 32°
Ans 23. (A): In ΔABD,
AD = BD (Given)
∠ABD = ∠DAB ( angle opposite to equal sides are equal)
Now, ∠ABD + ∠ADB + ∠DAB = 180° (Angle sum property of a triangle)
⇒ 2∠ABD + 88° = 180° ⇒ 2∠ABD = 180° – 88° = 92°
⇒ ∠ABD = 92° / 2 = 46°
As, DABC is an equilateral triangle,
so ∠CBA = 60°
⇒ x + ∠DBA = 60°
⇒ x + 46° = 60°
⇒ x = 60° – 46° = 14°
24. Solve:
A. xpq B. 1 / xpq
C. 1 D. xp-q
25. If 7 is multiplied with 8 more than a number, it becomes the same as 3 is added to 15 times the same number. This fact can be represented as ______.
A. 7(8 + x) = 3x – 15 B. 7x + 8 = 15x + 3
C. 7(8 + x) = 15x + 3 D. 7(8 – x) = 3x + 15
Ans 25. (C): Let the number be x.
According to question, 7(8 + x) = 15x + 3
26. Which of the following statements is correct?
A. If lengths of any two sides of a triangle are 8 cm and 11 cm, then the length of its third side lies between 3 cm and 19 cm.
B. It is possible to construct a unique triangle, if all its three angles are given.
C. An angle of 30°, can’t be constructed using compass and ruler.
D. A triangle can be constructed by taking two of its angles as 90° and 90°.
Ans 26. (A)
27. Subtract 18.569 from the sum of 208.056 and 48.685.
A. 215.640 B. 238.172
C. 198.642 D. 254.840
Ans 27. (B): Sum = 208.056 + 48.685 = 256.741
Required difference = 256.741 – 18.569 = 238.172
28. What should be subtracted from 7a3 + 6a2 – 2 – 5a to get 4a3 – 7a + 5a2+ 8 ?
A. 3a3 + a2 + 2a – 10
B. 4a3 - a2 - 2a + 8
C. -2a3 - a2 + 3a – 4
D. 3a3 - 2a2 + a – 5
Ans 28. (A): Let the required expression be X.
So, (7a3 + 6a2 – 2 – 5a) – X = 4a3 – 7a + 5a2+ 8
X = (7a3 + 6a2 – 2 – 5a) – (4a3 – 7a + 5a2+ 8)
= 7a3 + 6a2 – 2 – 5a – 4a3 + 7a – 5a2 – 8
= 3a3 + a2 + 2a – 10
29. Find the area of the given figure (not drawn to scale).
A. 152 cm2 B. 114 cm2
C. 108 cm2 D. 102 cm2
Ans 29. (C):
Area of rectangle ABCN = 12 × 3 = 36 cm2
As, MC = NC – NM = 12 – 3 = 9 cm
So, area of rectangle MLDC = 9 × 4 = 36 cm2
Area of rectangle KJIH = 5 × 3 = 15 cm2
As, GF = 14 – 3 – 4 = 7 cm
So, area of rectangle GFED = 7 × 3 = 21 cm2
Area of figure = (36 + 36 + 15 + 21) cm2 = 108 cm2
30. Which of the following options is incorrect?
A. x = 5 is the solution of 3x + 7 = 22.
B. The equation 3x + 5 = 13 represents “5 more than 3 times a number x gives 13”.
C. The solution of the equation 5x – 8 = 2 is x = 2.
D. The solution of the equation 10 – 3x = 1 is x = 4.
Ans 30. (D):
A. At x = 5 3x + 7 = 3(5) + 7 = 22
So, x = 5 is the solution of 3x + 7 = 22
B. Correct
C. 5x – 8 = 2 ⇒ 5x = 10 ⇒ x = 2
So, x = 2 is the solution of 5x – 8 = 2
D. 10 – 3x = 1 ⇒ –3x = – 9 ⇒ x = 3 ≠ 4
So, x = 4 is not the solution of 10 – 3x = 1.
31. Two numbers are in the ratio 7: 11. If 9 is added to each of the numbers, then ratio becomes 11: 16. The numbers are _______.
A. 28 and 44 B. 22 and 32
C. 44 and 64 D. 35 and 55
Ans 31. (D): Let the numbers be 7x and 11x.
According to question, 7x +9 / 11x + 9 = 11 / 16
⇒ 16(7x + 9) = 11(11x + 9)
⇒ 112x + 144 = 121x + 99
⇒ 121x – 112x = 144 – 99
⇒ 9x = 45 ⇒ x = 5
So, the numbers are 7 × 5 = 35 and 11 × 5 = 55.
32. In the given figure (not drawn to scale), ABC is a straight line, ∠DBE is a right angle and ∠a = ∠b = ∠c = ∠d. Find ∠a.
A. 22.5° B. 30°
C. 45° D. 60°
Ans 32. (A): Since, ABC is a straight line.
So, ∠a + ∠b + ∠c + ∠DBE + ∠d = 180°
⇒ 4∠a + 90° = 180° [ ∠a = ∠b = ∠c = ∠d]
⇒ 4∠a = 180° – 90° = 90° ⇒ ∠a = 90 4 ° = 22.5°
33. Which of the following figures do not have any line of symmetry?
34. A bag contains 30 blue ribbons, 15 red ribbons and 5 black ribbons. If a ribbon is drawn at random from the bag, then find the probability of getting a red ribbon.
A. 3/10 B. 5/12
C. 15/25 D. 2/11
Ans 34. (A): Total number of ribbons in the bag = 30 + 15 + 5 = 50
Probability of getting a red ribbon = Number of red ribbons in the bag /Total number of ribbons in the bag
= 15 / 50
= 3 / 10
35. Which of the following is greater than 16.3%?
A. 163 out of 1000 B. 113 out of 250
C. 8 out of 50 D. 39 out of 750
Ans;35. (B): 16.3% = 163 / 10% * 1 /100 =163 / 1000 = 0.163
A. 163 out of 1000 = 163 / 1000 = 0.163
B. 113 out of 250 = 113 / 250 = 0.452
C. 8 out of 50 = 8 / 50 = 0.16
D. 39 out of 750 = 39 / 750 = 0.052
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